2x^2-10x=5.5

Solution for 2x^2-10x=5.5 equation:

2x^2-10x=5.5

We move all terms to the left:

2x^2-10x-(5.5)=0

We add all the numbers together, and all the variables

2x^2-10x-5.5=0

a = 2; b = -10; c = -5.5;
Δ = b2-4ac
Δ = -102-4·2·(-5.5)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-12}{2*2}=\frac{-2}{4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+12}{2*2}=\frac{22}{4}
=5+1/2
$